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8^2+3r+2=7r^2
We move all terms to the left:
8^2+3r+2-(7r^2)=0
determiningTheFunctionDomain -7r^2+3r+2+8^2=0
We add all the numbers together, and all the variables
-7r^2+3r+66=0
a = -7; b = 3; c = +66;
Δ = b2-4ac
Δ = 32-4·(-7)·66
Δ = 1857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{1857}}{2*-7}=\frac{-3-\sqrt{1857}}{-14} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{1857}}{2*-7}=\frac{-3+\sqrt{1857}}{-14} $
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